Challenging Mathematical Problems with Elementary Solutions, 第 1 卷Holden-Day, 1964 - 440 頁 |
搜尋書籍內容
第 1 到 3 筆結果,共 13 筆
第 4 頁
... elements , and let us calculate the number of ways in which these elements can be ordered . There are k possibilities for the first element . Once it has been chosen , there are k - 1 possibilities for the second element ; once the ...
... elements , and let us calculate the number of ways in which these elements can be ordered . There are k possibilities for the first element . Once it has been chosen , there are k - 1 possibilities for the second element ; once the ...
第 4 頁
... elements , and let us calculate the number of ways in which these elements can be ordered . There are k possibilities for the first element . Once it has been chosen , there are k - 1 possibilities for the second element ; once the ...
... elements , and let us calculate the number of ways in which these elements can be ordered . There are k possibilities for the first element . Once it has been chosen , there are k - 1 possibilities for the second element ; once the ...
第 52 頁
... elements in A or B , but counts the elements of AB twice . So by subtracting # ( A ◇ B ) we get exactly the number of elements in AU B. 12b . Consider an element e which is in only one of the three sets , say in A. Then in the ...
... elements in A or B , but counts the elements of AB twice . So by subtracting # ( A ◇ B ) we get exactly the number of elements in AU B. 12b . Consider an element e which is in only one of the three sets , say in A. Then in the ...
其他版本 - 查看全部
常見字詞
A₁ A₂ An+m arrangements b₁ B₂ binomial coefficients binomial theorem bishops black squares C₁ chessboard chord circle coefficient color column compute the number Consequently consider corresponding customers denote determine the number diagonals digits dihedral angle divided divisible draw equally likely possible equation equidistant equivalence classes exactly example experiment favorable outcomes follows formula given Hence inclusion and exclusion intersection k-gons knights L₁ length mathematical induction maximum number n-gon number of different number of favorable number of paths number of shortest obtain pairs partition passengers plane points A1 polygons positive integers possible outcomes Pr{E probability theory problem 54 prove queens rectangle relatively prime remaining required probability rooks segment selected at random sequence shortest paths side solution to problem solved sphere square controlled Suppose T₂ total number triangle unfavorable values vertex vertices