Challenging Mathematical Problems with Elementary Solutions: Combinatorial analysis and probability theoryHolden-Day, 1964 |
搜尋書籍內容
第 1 到 3 筆結果,共 32 筆
第 147 頁
... five cards in the other hand , thus giving four favorable and five unfavorable outcomes . ( 2 ) 70b . The number of outcomes in which the 8 , 9 , and 10 are all in hand A is equal to the number of ways of choosing the two remaining ...
... five cards in the other hand , thus giving four favorable and five unfavorable outcomes . ( 2 ) 70b . The number of outcomes in which the 8 , 9 , and 10 are all in hand A is equal to the number of ways of choosing the two remaining ...
第 148 頁
... five games out of eight.2 72a . We consider here an experiment which consists of drawing k balls from a box ... five games out of eight . The point is that one must distinguish between the probability of winning exactly five games out of ...
... five games out of eight.2 72a . We consider here an experiment which consists of drawing k balls from a box ... five games out of eight . The point is that one must distinguish between the probability of winning exactly five games out of ...
第 172 頁
... five - dollar bills than there are with ten - dollar bills ahead of that point . In order for event B to occur , the first customer must have a five - dollar bill , and the remaining n + m . 1 customers must be arranged so that among ...
... five - dollar bills than there are with ten - dollar bills ahead of that point . In order for event B to occur , the first customer must have a five - dollar bill , and the remaining n + m . 1 customers must be arranged so that among ...
其他版本 - 查看全部
常見字詞
A₁ A₂ An+m arrangements b₁ B₂ binomial coefficients binomial theorem bishops black squares C₁ chessboard chord circle coefficient color column compute the number Consequently consider corresponding customers denote determine the number diagonals digits dihedral angle divided divisible draw equally likely possible equation equidistant equivalence classes exactly example experiment favorable outcomes follows formula G₁ given Hence inclusion and exclusion intersection k-gons knights length mathematical induction maximum number n-gon number of different number of favorable number of paths number of shortest obtain pairs partition passengers plane polygons positive integers possible outcomes Pr{E probability theory problem 54 prove queens rectangle relatively prime remaining required probability rooks S₁ segment selected at random sequence shortest paths side solution to problem solved sphere square controlled Suppose T₂ total number triangle unfavorable values vertex vertices