Challenging Mathematical Problems with Elementary Solutions: Combinatorial analysis and probability theoryHolden-Day, 1964 |
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第 1 到 3 筆結果,共 30 筆
第 142 頁
... outcomes ( one corresponding to each of the 10,000 bicycles which one might first encounter ) , 94 are favorable , from which it follows that the required probability is 94 / 10,000 = ( 0.9 ) 1 = 0.6561 . 65a . The experiment under ...
... outcomes ( one corresponding to each of the 10,000 bicycles which one might first encounter ) , 94 are favorable , from which it follows that the required probability is 94 / 10,000 = ( 0.9 ) 1 = 0.6561 . 65a . The experiment under ...
第 145 頁
... favorable outcomes are obviously the nine in which the right number comes up the first time and some other number the second time , and the nine outcomes in which one of the nine wrong numbers comes up the first time and the right ...
... favorable outcomes are obviously the nine in which the right number comes up the first time and some other number the second time , and the nine outcomes in which one of the nine wrong numbers comes up the first time and the right ...
第 148 頁
... outcomes in a set of four games is 24 16 , since each game has two possible outcomes . These are all equally likely , since A and B are equally strong . The favorable outcomes are those in which B wins only one game out of the four ...
... outcomes in a set of four games is 24 16 , since each game has two possible outcomes . These are all equally likely , since A and B are equally strong . The favorable outcomes are those in which B wins only one game out of the four ...
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A₁ A₂ An+m arrangements b₁ B₂ binomial coefficients binomial theorem bishops black squares C₁ chessboard chord circle coefficient color column compute the number Consequently consider corresponding customers denote determine the number diagonals digits dihedral angle divided divisible draw equally likely possible equation equidistant equivalence classes exactly example experiment favorable outcomes follows formula given Hence inclusion and exclusion intersection k-gons knights length mathematical induction maximum number multiple n-gon number of different number of favorable number of paths number of shortest obtain pairs partition passengers plane polygons positive integers possible outcomes Pr{E probability theory problem 54 prove queens rectangle relatively prime remaining required probability rooks S₁ segment selected at random sequence shortest paths side solution to problem solved sphere square controlled Suppose T₂ total number triangle unfavorable values vertex vertices