Challenging Mathematical Problems with Elementary Solutions: Combinatorial analysis and probability theoryHolden-Day, 1964 |
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第 1 到 3 筆結果,共 11 筆
第 92 頁
... queens which satisfy the condition imposed . ( See , for example , M. Kraitchik , Mathematical Recreations , New York , 1942 , p . 251. ) 41b . There cannot be more than one queen in any column of the chess- board ( since otherwise two ...
... queens which satisfy the condition imposed . ( See , for example , M. Kraitchik , Mathematical Recreations , New York , 1942 , p . 251. ) 41b . There cannot be more than one queen in any column of the chess- board ( since otherwise two ...
第 93 頁
... queens either in the same row or in adjacent rows ( otherwise these queens would control each other horizontally or diagonally ) . We will therefore try putting each queen in a row two away from that in which we put the preceding one ...
... queens either in the same row or in adjacent rows ( otherwise these queens would control each other horizontally or diagonally ) . We will therefore try putting each queen in a row two away from that in which we put the preceding one ...
第 94 頁
... queens to lie on the same positive diagonal as one of the second k queens . But this is impossible since the first k queens lie above the diagonal which joins the lower left - hand corner of the board to the upper right - hand corner ...
... queens to lie on the same positive diagonal as one of the second k queens . But this is impossible since the first k queens lie above the diagonal which joins the lower left - hand corner of the board to the upper right - hand corner ...
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常見字詞
A₁ A₂ An+m arrangements b₁ B₂ binomial coefficients binomial theorem bishops black squares C₁ chessboard chord circle coefficient color column compute the number Consequently consider corresponding customers denote determine the number diagonals digits dihedral angle divided divisible draw equally likely possible equation equidistant equivalence classes exactly example experiment favorable outcomes follows formula given Hence inclusion and exclusion intersection k-gons knights length mathematical induction maximum number multiple n-gon number of different number of favorable number of paths number of shortest obtain pairs partition passengers plane polygons positive integers possible outcomes Pr{E probability theory problem 54 prove queens rectangle relatively prime remaining required probability rooks S₁ segment selected at random sequence shortest paths side solution to problem solved sphere square controlled Suppose T₂ total number triangle unfavorable values vertex vertices