Challenging Mathematical Problems with Elementary Solutions, 第 1 卷Holden-Day, 1964 - 440 頁 |
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第 1 到 3 筆結果,共 48 筆
第 142 頁
... likely outcomes ( one corresponding to each of the 10,000 bicycles which one might first encounter ) , 9a are favorable , from which it follows that the required probability is 94 / 10,000 ( 0.9 ) 4 = 0.6561 . = 65a . The experiment ...
... likely outcomes ( one corresponding to each of the 10,000 bicycles which one might first encounter ) , 9a are favorable , from which it follows that the required probability is 94 / 10,000 ( 0.9 ) 4 = 0.6561 . = 65a . The experiment ...
第 145 頁
... outcomes are obviously the nine in which the right number comes up the first time and some other number the second ... possible outcomes for the first two people . Similarly we will have 123 equally likely possible outcomes for the first ...
... outcomes are obviously the nine in which the right number comes up the first time and some other number the second ... possible outcomes for the first two people . Similarly we will have 123 equally likely possible outcomes for the first ...
第 152 頁
... possible outcomes of a third hunter's drawing one of the slips , we obtain 27 equally likely possible outcomes . Of these 27 possible outcomes , one of the first two hunters draws the Hit slip in 35 15 cases ( remember that in the ...
... possible outcomes of a third hunter's drawing one of the slips , we obtain 27 equally likely possible outcomes . Of these 27 possible outcomes , one of the first two hunters draws the Hit slip in 35 15 cases ( remember that in the ...
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A₁ A₂ An+m arrangements b₁ b₂ binomial coefficients binomial theorem bishops black squares C₁ chessboard chord circle coefficient color column compute the number Consequently consider corresponding customers denote determine the number diagonals digits dihedral angle divided divisible draw equally likely possible equation equidistant equivalence classes exactly example experiment favorable outcomes follows formula G₁ given Hence inclusion and exclusion intersection k-gons knights length mathematical induction maximum number n-gon number of different number of favorable number of paths number of shortest obtain pairs partition passengers plane points A1 polygons positive integers possible outcomes Pr{E probability theory problem 54 prove queens rectangle relatively prime remaining required probability rooks segment selected at random sequence shortest paths side solution to problem solved sphere square controlled Suppose total number triangle unfavorable values vertex vertices